Ask question

Ask question

All categories

3 years ago

9

20 POINTS‼️‼️Which of the following does NOT represent the number of months in a year?

2 answers:

NeTakaya3 years ago

8 0

Answer:

B because when you multiply the first number by twelve the first two are correct but the second ones are not

Step-by-step explanation:

LenaWriter [7]3 years ago

5 0

Answer:

B

Step-by-step explanation:

12 times 6 = 72, not 60

You might be interested in

Simplify: (3 + 4i) + (2 - 3i) - (5 - 6i)

Sav [38]

(3 + 2 - 5) and (4i - 3i + 6i)
= 0 + 7i

5 0

3 years ago

Read 2 more answers

At a vacation resort, you can rent a jet ski for $35 per hour plus a $20 rental fee. your bill came to $90.

vaieri [72.5K]

Answer: $35 x 2 = $70 + $20 = $90

4 0

3 years ago

Read 2 more answers

3b +2f = 21.50 What is the Answer for B and F

Citrus2011 [14]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

b=7.1¯6−2f/3

Isolate the variable by dividing each side by factors that don't contain the variable.

f=10.75−3b/2

Step-by-step explanation:

5 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

2. Three bells P, Q and R ring at intervals of 40, 48and 60 minutes respectively. If they ring together at 6.15 a.m. when will t

MAXImum [283]

They will ring again together at 10:15am. Because the common factor for 40, 48 and 60 is 240, which means 240 minutes, that equals to 4 hours. Hence 4 hours after 6.15am is 10.15am.

Hope this helps.

5 0

3 years ago