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Your Question, -4(2x + 4) > 8x + 64 Solve for X
1) Expand -8x-16>8x+64
2) Add 16 to both sides -8x-16+16>8x+64+16
3) Simplify -8x>8x+80
4) Subtract 8x from both sides -8x-8x>8x+80-8x
5) Simplify -16x>80
6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)
7) Simplify 16x<-80
8) divide both sides by 16 16x/16 < -80/16
9) Simplify x < -5
This should be your answer x < -5
Hopefully that helps you :)
Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
this is your answer.............
Answer:
B
Step-by-step explanation: