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Naily [24]
3 years ago
11

Blank one

Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

1 IS B

Step-by-step explanation:

2 IS A

HOPE THIS HELPS

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
Read 2 more answers
10) xc = rd , for x<br><br> Help plz
ExtremeBDS [4]

Answer:

x = rd/c

Step-by-step explanation:

xc = rd

xc/c = rd/c

x = rd/c

8 0
2 years ago
Jojo likes to paint She estimates the number of paintings she completes using the function P(W) = w – 2. where w is the number o
KATRIN_1 [288]

Answer:

P[J(y)] = 2/3 * J(y) -2

Step-by-step explanation:

4 0
3 years ago
- 2x (a+h)^2+4(a+h)-12
hjlf
That’s the answer mama

7 0
3 years ago
H(-3), h(5), h(2), h(0)
romanna [79]

Answer:

h(-3) = -3h

h(5) = 5h

h(2) = 2h

h(0) = 0

5 0
2 years ago
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