To determine the name of an anion, you take the name of its element and replace the end with "ide".
<h3>What is an anion?</h3>
An anion in chemistry is a negatively charged ion.
Anions are usually formed when a non-metallic atom gains electron(s).
An anion is usually named by taking the elemental name, removing the ending, and adding “ide.
Examples of anions are as follows:
- fluoride (F-)
- Chloride (Cl-)
- Iodide (I-)
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Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.
<h3>What is bonding in molecules?</h3>
Bonding is a type of attraction force which is present between the different atoms or elements of any substance.
- Dipole dipole attraction force is a weak force as compared to the hydrogen bonding and present between any two oppositely charged atoms.
- Hydrogen bond is present between the hydrogen atom and more electronegative atoms like O, S, N and F.
Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.
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Answer:
Rubidium-85=61.2
Rubidium-87=24.36
Atomic Mass=85.56 amu
Explanation:
To find the atomic mass, we must multiply the masses of the isotope by the percent abundance, then add.
<u>Rubidium-85 </u>
This isotope has an abundance of 72%.
Convert 72% to a decimal. Divide by 100 or move the decimal two places to the left.
- 72/100= 0.72 or 72.0 --> 7.2 ---> 0.72
Multiply the mass of the isotope, which is 85, by the abundance as a decimal.
- mass * decimal abundance= 85* 0.72= 61.2
Rubidium-85=61.2
<u>Rubidium-87</u>
This isotope has an abundance of 28%.
Convert 28% to a decimal. Divide by 100 or move the decimal two places to the left.
- 28/100= 0.28 or 28.0 --> 2.8 ---> 0.28
Multiply the mass of the isotope, which is 87, by the abundance as a decimal.
- mass * decimal abundance= 87* 0.28= 24.36
Rubidium-87=24.36
<u>Atomic Mass of Rubidium:</u>
Add the two numbers together.
- Rb-85 (61.2) and Rb-87 (24.36)
Answer:
20L is the new volume
Explanation:
In this case, moles and T° from the gas remain constant. This is the formula we must apply, to solve this:
P₁ . V₁ = P₂ . V₂
5 atm . 10 L = P₂ . 2.5L
P₂ = (5 atm . 10 L) / 2.5L →20L
