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GuDViN [60]
3 years ago
8

Inbox

Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

8 oxygen. 9 flourine. 10. Neon. 5 Boron

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Match the vocabulary terms to their definitions.
vesna_86 [32]

Answer:

1. The standard metric unit of length is a meter.

2. A proposed explanation for a scientific problem is a hypothesis.

3. The standard unit of volume is a liter.

4. The curved top surface of a liquid column is the meniscus.

5. A quantity in an experiment that remains unchanges or constant is a controlled variable (control)

6. The amount of matter in an object is mass.

7 0
3 years ago
Read 2 more answers
Oxidation of Nitrogen in N2O3​
kirill [66]

Explanation:

<h3>oxidation of Nitrogen in N2O3 is </h3><h2>+3</h2>
7 0
2 years ago
How many moles are in 1.806 x 1024 molecules of bromine?
Pepsi [2]
<h3>Answer:</h3>

2.999 mol Br

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.806 × 10²⁴ molecules Br

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 1.806 \cdot 10^{24} \ molecules \ Br(\frac{1 \ mol \ Br}{6.022 \cdot 10^{23} \ molecules \ Br} ) = 2.999 mol Br

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

Our final answer is already in 4 sig figs, so there is no need to round.

7 0
2 years ago
Read 2 more answers
THIS ANSWER CORRECT?
damaskus [11]

Answer:

yes

Explanation:

7 0
2 years ago
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If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA     H⁺  +  A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid}     H⁺(aq)  +  A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ  + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0
3 years ago
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