Answer:
The answer is "2%"
Explanation:
Equation:


Formula:
![Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BNO_2%5E%7B-%7D%5D%7D%7B%5BHNO_2%5D%7D)
Let
at equilibrium

therefore,
![[H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%202.0%5Ctimes%2010%5E%7B-2%7D%20%5C%20M%20%3D%200.02%20%5C%20M)
Calculating the % ionization:
![= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%28%5BH%5E%7B%2B%7D%5D%7D%7B%5BHNO_2%5D%29%7D%20%5Ctimes%20100%20%5C%5C%5C%5C%3D%20%5Cfrac%7B0.02%7D%7B1%7D%5Ctimes%20100%20%5C%5C%5C%5C%3D%202%5C%25%5C%5C%5C%5C)
This reaction contains pure solids which are not considered when writing out equilibrium constant expressions.
O2...........SO2
I 2.9...........0
C -x.......... +x
E 2.9-x........ x
Q=0/2.9 = 0 ---->Q<K Reaction will go to the right
Since the coefficients are all 1, I won't bother putting in the exponents.
k=B/A
1.5= x / (2.9-x)
4.35 - 1.5x = x
2.5x = 4.35
x= 1.74
plug back in ice chart
2.9 - 1.74
=1.16
=1.2 ANSWER
A graduated cylinder. They are the most common method of getting a required volume of water. (other ways are using volume-metric pipets, graduated pipets, burets, syringes, and volume-metric flask. However these tools are a lot less common)
Answer:
hello, There!

<h2>
Your Question↓</h2><h3>
Which of the following are observations?</h3><h2>
Answer↓</h2>
❄ the candle floats, the tires are flat, and the dog is barking are observations.❄
Explanation:
↠ the three given statements are examples of observations, while the last two statements imply the concept of cause-effect relationships. ⬽
Have a great day! ⬽
Therefore, I hope this helps!
Answer:
Alcohols are prepared by SN2 reaction
Alkyl halides can be converted to alcohols by using SN2 reactions with OH- as a nucleophile. Substrates that undergo substitution by SN1 reaction can be converted to alcohols using water as the nucleophile (and it can even be the solvent).Explanation: