Answer:
That would be (2,3)
Step-by-step explanation:
When we're moving left in the coordinate plane, we are subtracting the x-coordinate by how much distance we move.
In this case, 7-5=2, so the new x-coordinate is 2, but the y-coordinate doesn't change since we're going horizontally and not vertically.
Answer:5/2a + 10/3b
Step-by-step explanation:
(1/6)(15a+20b)
=(1/6)(15a)+(1/6)(20b)
Answer:
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
So, the binomial probability distribution has two parameters, n and p.
In this problem, we have that and . So the parameter is
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Your answer would be b i'm pretty sure
let me edit your question as:
Which two equations are true?
<u>Eq1:</u>
(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)
<u>Eq2:</u>
6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)
<u>Eq3:</u>
2.7×103(7.5×106)−(2.5×106)=5×100
Answer:
No one is true
Step-by-step explanation:
let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.
Using PEMDAS rule we are simplifying the equations as;
<u>Eq1:</u>
<u>Eq2:</u>
<u></u><u></u>
<u>Eq3:</u>
<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>
<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>