Please help!!!!!!!!!!

ANY MATH EXPERTS PLS HELP RN I GOT 30 MIN LEFT I PUT 100 POINTS

Alexeev081 [22]

-8/5

Remember "rise over run." Rise means the vertical distance and run id the horizontal between the two points.

3 0

3 years ago

Read 2 more answers

The cloth top of the gazebo in Mr. Chang’s backyard has ripped from weathering. He needs to know the area of the cloth so he can

antoniya [11.8K]

Answer:

The correct answer is A. 60 square feet.

Step-by-step explanation:

1. Let's review the data provided to us for solving the question:

The gazebo in Mr. Chang's backyard, according to the figure, is a square pyramid because its base is a square of 6 feet as length of its sides.

Length of the sides of the base = 6 feet

Slant length = 5 feet

Height = 4 feet

2. How much cloth, in square feet, will Mr. Chang need, assuming he does not need to replace the cloth at the bottom of the figure?

Area of a square pyramid = Base area + 1/2 Perimeter * Slant length

Replacing with the real values, we have:

Area of a square pyramid = 6 * 6 + 1/2 (6 + 6 + 6 + 6) * 5

Area of a square pyramid = 36 + 1/2 (24) * 5

Area of a square pyramid = 36 + 12 * 5

Area of a square pyramid = 36 + 60

Area of a square pyramid = 96 feet ²

3. But remember than Mr. Chang doesn't need to replace the cloth at the bottom of the gazebo.

So we need to subtract the area of the base to the area of the square pyramid:

Area of the square pyramid - area of the base

Area of the base = 6 * 6 = 36 feet ²

96 feet ² - 36 feet ² = 60 feet ²

The correct answer is A. 60 square feet.

7 0

4 years ago

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Xavier needs to bike a minimum of 80 miles this week for his training. If he already biked 14 miles this week, then how many mil

ioda

Hi.

First, let's calculate how many miles he has left.

80 - 14 = 66

Now, to figure out how many miles a day in 6 days, divide.

66/6 = 11

Xavier should bike 11 miles on each of the 6 remaining days.

3 0

3 years ago

Find the value of x in ⊙Q .

ehidna [41]

Answer:

x= 5

Step-by-step explanation:

both lines are the same length

5x-6=2x+9

-2x -2x

3x-6= +9

+6 +6

3x = 15

÷3 ÷3

x= 5

6 0

3 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

3 years ago