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2 years ago

Which statement best describes the effects on the graph of f(x)=3x when f(x) is replaced by −3f(x+7)−2?

Mathematics

1 answer:

d1i1m1o1n [39]2 years ago

5 0

Answer: to move a graph up c units, add c to the whole function

so basicaly what you did is you subtraced 3 from the whole function

the whole graph shifts 3 units down

B is answer

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

you divide 30 by 12 because he practices piano 12/30 days of the month

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Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

2 years ago

Before a race, Evelyn ran 27 minutes to warm up. The race took her 2 hours.

Gwar [14]

Answer:

C. 147 minutes

Step-by-step explanation:

This is 147 minutes because 2 hours equal up to 120 minutes, before that Evelyn ran 27 minutes. So, now you have to add 120 and 27. You get 147.

4 0

2 years ago