I would say Solar Power Engineer.
Well, where is the table at?
If you, don't have the table then try going with D. Valley. I hope this helps :)
a=Δv/Δt=(v-v₀)/t=(46.1-18.5)/2.47=27.6/2.47=11.17 m/s²
d=v₀t+at²/2=18.5*2.47+11.17*2.47²/2=45.69+34.08=79.776 m
Answer:
E. 0.25
Explanation:
Given that
Angular speed ω = 3.5 rad/s
Distance ,r= 0.2 m
Lets take mass of dust bunny = m
We know that
Radial force F = m ω² r
The friction force on the dust bunny Fr
Fr= μ m g
To getting slung off dust bunny from disk
m ω² r = μ m g
ω² r = μ g
3.5² x 0.2 = μ x 10 ( take g =10 m/s²)
μ = 0.245
μ = 0.25
Therefore answer is E
E. 0.25
The answer is 0 because of the velocity “u” doesn’t A