All categories

3 years ago

What percentage of the net income earned in the United States is generated by corporations?

1 answer:

azamat3 years ago

4 0

<span>The correct answer is C. 60. A more precise answer would be around 70, but this is the closest one we have. As a matter of fact, 50% of the net income is made by only 5% of companies, while the remaining US corporations raise the bar to around 70. These 5% are mostly conglomerates that deal in all areas of business, from food to cosmetics to furniture.</span>

You might be interested in

What is released when rocks shift or move along a tectonic plate boundary?

Phoenix [80]

Answer:

juuhu

Explanation:

jjj

6 0

2 years ago

An incident light ray strikes water at an angle of 20 degrees. The index of refraction of air is 1.0003, and the index of refrac

sammy [17]

In order to determine the angle of the refracted ray, we may apply Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is constant for a given wave when it passes through two different media. Mathematically, this is:
n₁sin(∅₁) = n₂sin(∅₂)
Where n is the refractive index. Substituting the values given into the equation:
1.0003 * sin(20°) = 1.33 * sin(∅)
∅ = 14.91

The angle of the refracted ray is 15°.

4 0

3 years ago

Read 2 more answers

Please select the word from the list that best fits the definition Visualizes where items are located

Amanda [17]

Answer:I’m pretty sure it’s spatial

Explanation:

3 0

3 years ago

Read 2 more answers

Marcus drove his Honda Prelude for 4 hours at a rate of 55 miles per hour. How far did he travel?

Leto [7]

D.220 miles is the correct answer

5 0

3 years ago

Read 2 more answers

Ask Your Teacher In the air over a particular region at an altitude of 500 m above the ground, the electric field is 120 N/C dir

strojnjashka [21]

Answer:

$1.475\times 10^{-13}\ C/m^3$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

A = Area

h = Altitude = 600 m

Electric flux through the top would be

$-110A$ (negative as the electric field is going into the volume)

At the bottom

$120A$

Total flux through the volume

$\phi=120-110\\\Rightarrow \phi=10A$

Electric flux is given by

$\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=10A\epsilon_0$

Charge per volume is given by

$\rho=\dfrac{q}{v}\\\Rightarrow \rho=\dfrac{10A\epsilon_0}{Ah}\\\Rightarrow \rho=dfrac{10\epsilon_0}{h}\\\Rightarrow \rho=\dfrac{10\times 8.85\times 10^{-12}}{600}\\\Rightarrow \rho=1.475\times 10^{-13}\ C/m^3$

The volume charge density is $1.475\times 10^{-13}\ C/m^3$

7 0

3 years ago