Answer:
4.35×10⁻⁴ m
Explanation:
(a)
From wave,
v = λf...................... Equation 1
Where v = speed of sound in air, λ = wavelength of sound, f = frequency of sound.
Make λ the subject of formula in equation 1
λ = v/f................. Equation 2
Given: v = 343, f = 3.45 MHz = 3.45×10⁶ Hz
Substitute into equation 2
λ = 343/(3.45×10⁶)
λ = 99.42×10⁻⁶ m
λ = 9.942×10⁻⁵ m
(b)
using,
v' = λ'f............... Equation 3
Where v' = speed of sound in tissue, λ' = wavelength of sound in tissue.
make λ' the subject of the equation
λ' = v'/f......................Equation 4
Given: v' = 1500 m/s, f = 3.45 MHz = 3.45×10⁶ Hz
Substitute into equation 4
λ' = 1500/(3.45×10⁶)
λ' = 434.783×10⁻⁶
λ' ≈ 4.35×10⁻⁴ m.
Answer:
1) No, the car does not travel at constant speed.
2) V = 9 ft/s
3) No, the car does not travel at constant speed.
4) V = 5.9 ft/s
Explanation:
In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:
V(t) = 2*t + 2 Since the speed depends on time, the speed is not constant at any time.
For the average speed we evaluate the formula for t=2 and t=5:
d(2) = 8 ft and d(5) = 35 ft

Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:
d(1.8) = 6.84 ft and d(2.1) = 8.61 ft

Answer:
Magnetic field, B = 0.275 T
Explanation:
Given that,
Length of the wire, L = 35 cm = 0.35 m
Current carried in the wire, I = 2.6 A
The segment makes an angle of 53∘ with the direction of the magnetic field, 
Magnetic force, F = 0.2 N
To find,
The magnitude of the magnetic field.
Solution,
The magnetic force acting on the wire is given by :

is the angle between the length of wire and the magnetic field.

B = 0.275 T
Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.