Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed
![v_{1}=\dfrac{3.0\times10^{3}}{3600}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Cdfrac%7B3.0%5Ctimes10%5E%7B3%7D%7D%7B3600%7D)
![v_{1}=0.833\ m/s](https://tex.z-dn.net/?f=v_%7B1%7D%3D0.833%5C%20m%2Fs)
The force F₁is constant acceleration is also a constant.
![F_{1}=ma_{1}](https://tex.z-dn.net/?f=F_%7B1%7D%3Dma_%7B1%7D)
We need to calculate the acceleration
Using formula of acceleration
![a_{1}=\dfrac{v}{t}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cdfrac%7Bv%7D%7Bt%7D)
![a_{1}=\dfrac{0.833}{10}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cdfrac%7B0.833%7D%7B10%7D)
![a_{1}=0.083\ m/s^2](https://tex.z-dn.net/?f=a_%7B1%7D%3D0.083%5C%20m%2Fs%5E2)
Similarly,
![F_{2}=ma_{2}](https://tex.z-dn.net/?f=F_%7B2%7D%3Dma_%7B2%7D)
For total force,
![F_{3}=F_{2}+F_{1}](https://tex.z-dn.net/?f=F_%7B3%7D%3DF_%7B2%7D%2BF_%7B1%7D)
![ma_{3}=ma_{2}+ma_{1}](https://tex.z-dn.net/?f=ma_%7B3%7D%3Dma_%7B2%7D%2Bma_%7B1%7D)
The speed of second tugboat is
![v=\dfrac{11\times10^{3}}{3600}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B11%5Ctimes10%5E%7B3%7D%7D%7B3600%7D)
![v=3.05\ m/s](https://tex.z-dn.net/?f=v%3D3.05%5C%20m%2Fs)
We need to calculate total acceleration
![a_{3}=\dfrac{v}{t}](https://tex.z-dn.net/?f=a_%7B3%7D%3D%5Cdfrac%7Bv%7D%7Bt%7D)
![a_{3}=\dfrac{3.05}{10}](https://tex.z-dn.net/?f=a_%7B3%7D%3D%5Cdfrac%7B3.05%7D%7B10%7D)
![a_{3}=0.305\ m/s^2](https://tex.z-dn.net/?f=a_%7B3%7D%3D0.305%5C%20m%2Fs%5E2)
We need to calculate the acceleration a₂
![0.305=a_{2}+0.083](https://tex.z-dn.net/?f=0.305%3Da_%7B2%7D%2B0.083)
![a_{2}=0.305-0.083](https://tex.z-dn.net/?f=a_%7B2%7D%3D0.305-0.083)
![a_{2}=0.222\ m/s^2](https://tex.z-dn.net/?f=a_%7B2%7D%3D0.222%5C%20m%2Fs%5E2)
We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂
![\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}](https://tex.z-dn.net/?f=%5Cdfrac%7BF_%7B1%7D%7D%7BF_%7B2%7D%7D%3D%5Cdfrac%7Bm%5Ctimes0.83%7D%7Bm%5Ctimes0.22%7D)
![\dfrac{F_{1}}{F_{2}}=3.7](https://tex.z-dn.net/?f=%5Cdfrac%7BF_%7B1%7D%7D%7BF_%7B2%7D%7D%3D3.7)
![F_{1}=3.7F_{2}](https://tex.z-dn.net/?f=F_%7B1%7D%3D3.7F_%7B2%7D)
Hence, The magnitude of F₁ is 3.7 times of F₂
Answer:
Velocity of both masses after the collisio
Explanation:
Hope it will help
<h2>
<em><u>Brainlists please</u></em></h2>
The extrapolated temperature is used to define the maximum temperature of the mixture relatively than the highest recorded temperature in which the conclusion will effect in a higher specific heat value. Heat is bound to escape from whatever apparatus is using, therefore it is needed to account for the loss of the heat that does not go into increasing the temperature of the mixture.
Answer:
I think c is the answer but I have a little concern on d too