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Tomtit [17]
3 years ago
14

if you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one y

ear (not a leap year), what will be the value of your entire savings, in dollars, at the end of that one year? Express your answer as a decimal.
Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

2003.85

Step-by-step explanation:

I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.

You have save by an increasing amount of 3 pennies per day. You start with 3 and build from that, each day, for 365 days. First, you must figure out what amount of pennies you shoved into your account on the final 365th day.

An= a1+(n-1)d

An=term you want

a1= term you begin with

n= term you want

d= constant amount

A_365= 3 + (365-1)*3

A_365= 1095

Arithmetic Sum: Sn = N/2 (a1 + an)

365/2 * (3 + 1095) = 200385.

This means you've invested a total of 200385 PENNIES after 365 days.

The question asks for dollars, not your rusting lincoln's.

As (I hope) you know, 1 Dollar = 100 pennies

200385 pennies/100 = 2003.85.

This means you have $2003.85 in your account by the conclusion of the 365th day.

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16x 2 + 8x - 15 Mathematics?
Gala2k [10]
If you're factoring, your answer is

(4x - 3)(4x + 5)

You'll work it out this way:

16x^2 + 8x - 15

Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:

16x^2 + 20x - 12x - 15

From here you divide it into two binomials. These are (16x^2 + 20x) and (-12x - 15).
When you take out the greatest common factors (4x and -3), they become:

4x(4x + 5) - 3(4x + 5)

Then you group what's outside of the parentheses together (4x - 3)
And bring what's inside of the parentheses down (4x + 5).
This brings your answer to

(4x - 3)(4x + 5)
5 0
3 years ago
Given sec(theta)= 5... find cot(90-theta)
Mumz [18]
\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 }  = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6}  
\\

3 0
3 years ago
The polynomial f(x) leaves a remainder of - 3 and - 7 when divided by (3x - 1) and (x +1) respectively.
olga55 [171]

Step-by-step explanation:

Here, f(x) is the given polynomial.

By remainder Theorem,

When divided by (3x-1),

f(1/3) = -3........(1)

When divided by (x+1),

f(-1) = -7.........(2)

<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>

Solving,

3x²+2x-1

= 3x²+3x-x-1

=3x(x+1)-(x+1)

=(3x-1)(x+1)

So

f(x) = (3x-1)(x+1)Qx + (ax+b)

For f(-1),

-7 = -a+b

b= a-7

For f(1/3),

-3 = a/3+b

or, -3 = a/3+a-7

or, 4×3 = 4a

or a = 3

Also, b = 3-7 =-4

Hence, remainder is (3x-4)

7 0
3 years ago
PLS HELPPLS PLS PLS ILL GIVE BRAINLY
olga nikolaevna [1]
The answer to this question is c I think
8 0
3 years ago
Read 2 more answers
Evaluate this expression for c=6, and a=2. c/a.
yan [13]

Answer:

We know that....

c=6

a=2

so c/a = 6/2 = 3

Hope this helps....

Have a nice day!!!!!

Mark my ans as brainliest ang get 3 extra points

4 0
3 years ago
Read 2 more answers
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