15. = slope would be 7 and y-int would be -4
16. = slope would be -2/5 and y-int would be 0
17. = doesn’t have a y variable
slope intercept form is y=mx+b with the m being the slope and the b being the y-int. in some cases where the equation is not in this form you have to change it so it is in that form by using opposite operations
Answer:
The maximum revenue is 16000 dollars (at p = 40)
Step-by-step explanation:
One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.
Given function is:

Taking derivative wrt p

Now putting R'(p) = 0

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40
Putting p=40 in function

The maximum revenue is 16000 dollars (at p = 40)
Angle 1 is congruent to angle 7