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3 years ago

11

You have twenty blankets that each take up 704 cubic inches of space. How many blankets could you pack into a 22-inch moving box

?

2 answers:

Vsevolod [243]3 years ago

5 0

Answer:

32

Step-by-step explanation:

i don't know if its right but i did 704 divided by 22 which equals to 22

Karolina [17]3 years ago

4 0

Answer:

15

Step-by-step explanation:

I took the test and got it correct

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I need help finding this problem out please

Sergio [31]

Answer: what’s the problem

Step-by-step explanation:

3 0

3 years ago

Assume that the function call operator() is overloaded for data type String in the usual sense of selecting a substring from a l

krek1111 [17]

Answer:

"EF"

Step-by-step explanation:

Given

String1 = "ABCDEFGHI"

Substring : String1(4,2)

To solve this, one must understand the following

1. The function call operator () is used to overload objects of class type.

2. A copy constructor must receive its argument by reference to prevent an otherwise infinite recursion.

3. overload ( ), doesn't mean that one is not creating a new way to call a function; instead, it is a way to create an operator function that can be passed an arbitrary number of parameters

Having pointed out this,

The string to overload goes thus

String1 = "ABCDEFGHI"

The parameters goes thus

String1(4,2)

To represent this properly, we have

("ABCDEFGHI",4,2)

Which means to return 2 strings starting from the 4th index character.

It should be noted that index starts at 0.

So, the character at the 4th index is "E"

Then, we count 2 characters starting from E (i.e. E, inclusive)

This gives

"EF"

So, the returned string is "EF"

6 0

3 years ago

Ralph is an electrician. He charges an initial fee of $26, plus $31 per hour. If Ralph earned $119 on a job, how long did the jo

lubasha [3.4K]

3 hours

You can turn this into an equation:

F = 26 + 31t
Where F is the money Ralph earned, and t is the number of hours he worked.

Plugging in the 119 for F, we get
119 = 26 + 31t

93 = 31t

3 = t

5 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

Need help on number 1, 5 and 7

zimovet [89]

Answer:

1) y = (x + 8)² + 7; 5) y = (x - 6)² + 10; 7) y = (x - 3)² - 4

Step-by-step explanation:

Complete the square in order to figure these out. To complete the square, use the formula <em>[½B]</em><em>²</em><em>.</em><em> </em>Each time you do this, you get a perfect trinomial in the form of a product of two monomials [<em>h</em>], then you have to figure out how much more to deduct from or add on to your <em>C</em><em> </em>they gave you in each exercise [<em>k</em>].

If you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD].

I am joyous to assist you anytime.

4 0

3 years ago