All categories

3 years ago

Find the midpoint rounded to the nearest hundreth a (-2,1) b (-1,1)

Mathematics

1 answer:

Veronika [31]3 years ago

8 0

Answer:

$(-1.5, 1)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

Endpoint A (-2, 1)

Endpoint B (-1, 1)

Step 2: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-2-1}{2},\frac{1+1}{2})$
Subtract/Add: $(\frac{-3}{2},\frac{2}{2})$
Divide: $(-1.5, 1)$

You might be interested in

The cost of 2kg apples and 3 kg oranges is Rs. 120. [Take x and y as the cost per kg of apples and oranges respectively.]

stiv31 [10]

Step-by-step explanation:

2+3=120

5=120

=120

=24

apple=2 multiply 24 is 48

orange=3 multiply 24 is 72

6 0

1 year ago

The surveyor sets up the instrument to determine the height at the highest point on the hill. She determines that she is standin

Ne4ueva [31]

Answer:

$(a)\ h = d * \tan(\theta)$

$(b)\ h = 30.57m$

Step-by-step explanation:

Given

$\theta = 17^o$

$d =100m$

$h = ??$

See attachment for illustration

Solving (a): Trigonometry ratio to calculate h.

From the attachment, we have:

$\tan(\theta) = \frac{h}{d}$

Multiply both sides by d

$d * \tan(\theta) = \frac{h}{d} * d$

$d * \tan(\theta) = h$

Rewrite as:

$h = d * \tan(\theta)$

Solving (b): The value of h

We have:

$\theta = 17^o$

$d =100m$

So:

$h = 100m * \tan(17^o)$

$h = 100m * 0.3057$

$h = 30.57m$

8 0

3 years ago

Select the correct answer. The edges of a cube are 5 centimeters each and the diagonal of a face is approximately 7 centimeters.

kow [346]

C : 35

---------------------

6 0

3 years ago

Read 2 more answers

Α' β

yulyashka [42]

Answer:

8x² +36x -27=0

Step-by-step explanation:

2x²= 6x +3

Let's rewrite the equation into the form of ax²+bx+c= 0.

2x² -6x -3=0

Thus, a= 2

b= -6

c= -3

Sum of roots= $- \frac{b}{a}$

Since your roots are p and q, sum of roots= p +q

p +q= $- (\frac{ - 6}{2} )$

p +q= 6 ÷2

p +q= 3

Product of roots= $\frac{c}{a}$

pq= $- \frac{3}{2}$

Quadratic equations:

x² -(sum of roots)x +(product of roots)= 0

Thus, we have to find the sum and the product of the new roots, p²q and pq².

p +q= 3

pq= -3/2

Product of new roots

= (p²q)(pq²)

= p³q³

= (pq)³

$= ( - \frac{3}{2} )^{3} \\ = - \frac{27}{8}$

sum of new roots

= p²q +pq²

= pq(p +q)

= (-3/2)(3)

= -9/2

Thus, the quadratic equation with roots p²q and pq² is

x² -(-9/2)x -27/8 = 0

$x ^{2} + \frac{9}{2} x - \frac{27}{8} = 0$

Multiply by 8 throughout:

$8 {x}^{2} + 36x - 27 = 0$

3 0

3 years ago

Will mark as Brainiest answer if you help ASAP!

spayn [35]

Vertex is $(x+5)^2+12$ and minimum value of f(x) is 12
Hope this helps

6 0

4 years ago