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larisa [96]
3 years ago
5

I need help on this question

Mathematics
1 answer:
rewona [7]3 years ago
8 0

x = -7

hope this helps!

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A card game has 50 cards. After dealing 7 cards to each player, tupi has 15 cards left over. solve the equation
KIM [24]
50 - 15 = 35

35 ÷ 7 = 5

So there were 5 players and your equation would be:-

50 - 15 ÷ x = 5

x = 7

Hope i helped:P  
5 0
3 years ago
11x<-66 what is the answer
melomori [17]
11 x < - 66

x < - 66 / 11

x < - 6

hope this helps!
8 0
3 years ago
Your grandfather placed $5,000 in a trust fund for you. In 12 years, the fund will be
PolarNik [594]

Answer:

fv/pv=(1+r)^n

10,000/5000=(1+r%)^12

2=(1+r%)^12

r= 5.95

4 0
3 years ago
Read 2 more answers
Please help seems easy just can’t figure out the answer
madreJ [45]

Answer:

b is 125

Step-by-step explanation:

8 0
3 years ago
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0
3 years ago
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