Answer:
Step-by-step explanation:
Given that acceleration of an object is

is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0

So solution for distance is

9.285714285714286 645=650 69=70
8-3(2)
8-5
=3
the answer should be 3 after plugging in the variables.
The answer is...
1. B
2. B
3. B
4.C
5.C
1)81° due to the fact that 99° and (1) are supplementary angles
2)99° due to the fact that (5) and (2) are adjacent angles that sum up to equal 180°
3)81° due to the fact that it is the corresponding angle to (5)
4)99° due to the fact that (4) and (2) are alternate interior angles which equal the same
5)81° due to the fact that (5) and (6) are adjacent angles which means they are supplementary angles that add to equal 180°
6)99° due to the fact that (6) and (2) are corresponding angles which equal the same value
7)81° due to the fact that (7) and (3) are corresponding angles with equal the same degree