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Dimas [21]
3 years ago
9

F(x)=2x+3/4x+5find f(-9)​

Mathematics
2 answers:
mylen [45]3 years ago
6 0

\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

f(x) =  \frac{2x + 3}{4x + 5} \\

For f(-9), put "-9" for every value of "x".

↬f( - 9) =  \frac{2( - 9) + 3}{4( - 9) + 5}\\

↬ f(-9) =  \frac{ - 18 + 3}{ - 36 + 5} \\

↬ f(-9) =  \frac{ - 15}{ - 31}\\

↬ f(-9)=  \frac{15}{31}\\

↬f(-9)=  0.48\\

\bold{ \green{ \star{ \red{Mystique35}}}}⋆

zhenek [66]3 years ago
6 0

\huge\textsf{Hey there!}

\mathsf{f(x) = \dfrac{2x + 3}{4x + 5}}

\mathsf{y = \dfrac{ 2x + 3}{4x + 5}}

\mathsf{y = \dfrac{2(-9) + 3}{4(-9) + 5}}

\mathsf{2(-9)}

\mathsf{\bf = -18}

\mathsf{y = \dfrac{-18 + 3} {4(-9) + 5}}

\mathsf{-18 + 3}\\\mathsf{= \bf -15}

\mathsf{y = \dfrac{ -15} {4(-9) + 5}}

\mathsf{4(-9)}\\\mathsf{\bf = -36}

\mathsf{y = \dfrac{-15}{-36 + 5}}

\mathsf{-36 + 5}\\\mathsf{= \bf-31}

\mathsf{y = \dfrac{-15}{ -31}\rightarrow\boxed{\bf \dfrac{15}{31}}}

\boxed{\boxed{\huge\text{Answer: } \boxed{\bf f(-9) = \dfrac{15}{31}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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A rectangular carpet has a perimeter of 274 inches. The length of the carpet is 95 inches more than the width. What are the dime
GrogVix [38]

Answer:

Length: 116

Width: 21

Step-by-step explanation:

Let's say that the width of carpet is x. If the length of the carpet is 95 inches more than the width, then let's say that the width is x + 95.

Since we are solving for the perimeter, you have to multiply the width and the length(x and x + 95) by two.

So,

2x + 2x + 190 = 274.

Simplify this and you get:

4x= 274 - 190

4x = 84

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So, the width is 21. This means that the length is 21 + 95.

21 + 95 = 116

4 0
3 years ago
Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...
oksano4ka [1.4K]

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

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a₁₃ = - 3x + 7 + 12(- 2x - 4)

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3 0
3 years ago
Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position
Alenkinab [10]

Answer:

\cos \theta=-\dfrac{8}{17}

Step-by-step explanation:

Coordinates of Point b=(-8,15)

b lies on the circle whose equation is x^2+y^2=289

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Comparing with the general form a circle with center at the origin: x^2+y^2=r^2

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

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8 0
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