A 26.3 kg space rock is pushed with a force and accelerates at 12.82 m/s/s. How much force was applied?

Physics

1 answer:

Kazeer [188]3 years ago

6 0

Answer: multiply mass and acceleration, unit is N (newtons)

Explanation: law of dynamics: F = ma

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what kinds of investigations might have led to our current understanding of matter and energy? why is it important for scientist

lana66690 [7]

The kind of investigations might have led to our current understanding of matter and energy is research and measurement.

It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

<h3>What is matter?</h3>

The matter has volume and space occupied.

When conceivable the researcher endeavors to test his speculations via painstakingly planned and controlled tests that will yield quantitative instead of subjective outcomes.

Thus, the kind of investigations might have led to our current understanding of matter and energy is research and measurement.

It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

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6 0

2 years ago

The human tibia breaks under an impulse of 55 Ns. If after falling a person typically comes to eat in a time span of 0.005 s how

ozzi

Answer:

0.73 m/s

Explanation:

From Newton second law of motion,

I = m(v-u)...................... Equation 1

Where I = Impulse, m = mass of the person, v = final velocity, u = Initial velocity.

make v the subject of the equation

v =(I/m)+u................. Equation 2

Note: u = 0 m/s as the person is falling from an height.

Given: I = 55 Ns, m = 75 kg, u = 0 m/s

Substitute into equation 2

v = 55/75

v = 0.73 m/s

5 0

4 years ago

4. A 1,000-kilogram satellite completes a uniform circular orbit of radius 8.0 x 10 meters as

lesantik [10]

Answer:

Zero

Explanation:

The work done by a force on an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and the displacement of the object

In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so $\theta=90^{\circ}$ and $cos \theta =0$ . Therefore, the work done by gravity is also zero.