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3 years ago

A ball rolls across the floor at a constant speed, what will happen to it if there is no friction?

Physics

1 answer:

Pepsi [2]3 years ago

7 0

the ball will stay moving at the same rate of speed until something happens and stop it

You might be interested in

Does the inertia of an object change as the object’s velocity changes explain

Sever21 [200]

Inertia is proportional to mass. It is a measure of the resistance to changes in velocity. Inertia is a property of mass and cannot change. Momentum changes as an object changes its velocity. Good luck on your assignment and have a great day! :D

8 0

3 years ago

A point charge Q at the center of a sphere of radius R produces an electric flux of Î¦ coming out of the sphere. If the charge r

Dafna1 [17]

Remains the same

Explanation:

According to Gauss's law, the electric flux through a closed surface is proportional to the charge enclosed by the surface. So no matter how big or small we make the surface that encloses the charge, the electric flux remains the same because it only depends on the enclosed charge, not surface area.

3 0

3 years ago

A 5000kg car traveling at 40m/s crashes into a wall and comes to a complete stop in 10ms. What was the force on the wall?

Kisachek [45]

Answer:

20,000,000 N

Explanation:

First find the acceleration:

a = Δv / Δt

a = (0 − 40 m/s) / 0.010 s

a = -4000 m/s²

Next use Newton's second law to find the force on the car:

F = ma

F = (5000 kg) (-4000 m/s²)

F = -20,000,000 N

According to Newton's third law, the force on the wall is equal and opposite the force on the car.

F = 20,000,000 N

7 0

3 years ago

A projectile is fired upward at an angle θ above the horizontal with an initial speed v0. At its maximum height, what are its ve

aliya0001 [1]

Answer:

$\vec{v}_{\rm max} = v\cos(\theta)(\^x)\\|\vec{v}_{\rm max}| = v\cos(\theta)\\\vec{a} = \vec{g} = -9.8\^y$

Explanation:

The equations of kinematics will be used to solve this question:

$y - y_0 = v_{y_0}t + \frac{1}{2}a_yt^2\\v_y^2 = v_{y_0}^2 + 2a_y(y - y_0)\\v_y = v_{y_0} + a_yt$

At its maximum height, the projectile has zero velocity in the y-direction. But its velocity in the x-direction is unaffected.

First, let's apply the above equations to the x-direction.

There is no acceleration in the x-direction. So, its velocity in the x-direction is constant during the motion.

$v_x = v_{x_0} + a_xt = v_{x_0} + 0\\v_x = v_{x_0} = v\cos(\theta)$

Therefore, the velocity vector of the projectile is

$v_{max} = v_x = v\cos(\theta)$

The speed of the projectile is the same.

The acceleration vector is constant during the motion and equal to the gravitational acceleration, which is -9.8 downwards.

7 0

4 years ago

Help!!!! A loop of area 0.100 m^2 is oriented at 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0

Nat2105 [25]

Answer:

Resulting Change in the Magnetic Flux $=0.013\:Wb$

Explanation:

Thanks!

3 0

4 years ago