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2 years ago

15

Figure ABCD is a kite.

2 answers:

Kay [80]2 years ago

7 0

Answer:

It's 14..... I just took the quiz

Anestetic [448]2 years ago

7 0

Answer:

its 14

Step-by-step explanation:

i did it on edge 2021

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Along with this one please

Anarel [89]

X=5.2
Hope this was helpful

8 0

3 years ago

Using quadratic form 6x^2-8x+3=0

LenaWriter [7]

x=8+sqrt-8/12, x=8-sqrt-8/12

I think...

5 0

3 years ago

Here’s the question!!!

ludmilkaskok [199]

Answer:

The answer is 3/4 because 2/4 + 1/4 = 3/4.

7 0

3 years ago

The cost to manufacture t shirts can be represented by the function c(x)=10.5x complete the following statement about the functi

Advocard [28]

For this case we have:

Cost of manufactures of T-shirts $C(x)=10.5x$

where x represents the number of T-shirts

Part A:

Substituting $x = 8$ in the total cost equation you have to:

$C (8) = (10.5) (8)\\\\C (8) = 84\\$

Thus, the cost of 8 shirts will be $C (8) = 84\\$

Part B:

If $x = 12$ then

$C (12) = (10.5) (12)\\\\C (12) = 126\\$

Thus, the cost of 12 shirts will be $C (12) = 126\\$

Answer:

$C (8) = 84\\\\C (12) = 126\\\\$

8 0

3 years ago

Read 2 more answers

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago