Let
x--------> the first <span>odd integer
x+2-----> </span>the second odd integer
x+4-----> the third odd integer
we know that
6(x+2)-2x=20+(x+2)+(x+4)
6x+12-2x=26+2x
4x-2x=26-12
2x=14
x=7
the answer is
the numbers are
7, 9 and 11
2.25/0/00075 = 3000
There will be 3000 sheets of paper
the total height of the stack is 2.25
Answer:
42
Step-by-step explanation:
8+8+12+4+4+3+3
Something like this for the problem.
<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
