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Mamont248 [21]
3 years ago
6

HELP WILL GIVE BRAINLIEST IF CORRECT

Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer:

B. No, the remainder is -50.

General Formulas and Concepts:

<u>Algebra I</u>

  • Roots are when the polynomial are equal to 0

<u>Algebra II</u>

  • Synthetic Division

Step-by-step explanation:

<u>Step 1: Define</u>

Function f(x) = x³ - 10x² + 27x - 12

Divisor/Root (x + 1)

<u>Step 2: Synthetic Division</u>

<em>See Attachment.</em>

To determine whether a given root is an actual root, the remainder must equal 0. Since we have a remainder of -50, the given root is not a factor of the polynomial.

<em>Please excuse the bad handwriting. Hope this helped!</em>

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x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

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