Question

A seal went 15 below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a larger fish. What expression represents the sea lion's position in relation to sea level?

Answer 1

Answer:

$2\times 15-6 = 24\ below\ sea\ level$

Step-by-step explanation:

Given that:

Distance traveled by seal to catch the fish = 15 below sea level

Sea lion wanted to catch a larger fish so sea lion dove 6 feet lesser than two time the distance that the seal traveled.

To find:

The expression to represent the position of the sea lion in the sea.

Solution:

If the distance traveled by seal is represented by $D$ then as per the question statement:

Twice of $D$ = $2\times D$

6 lesser than twice of $D$ = $2\times D$ - 6

Now, putting the value of $D$ = 15

Therefore, the expression to represent the sea lion's position w.r.to sea level.

$2\times 15-6\\ = 24\ below\ sea\ level$