A seal went 15 below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a larger
1 answer:
Answer:
Step-by-step explanation:
Given that:
Distance traveled by seal to catch the fish = 15 below sea level
Sea lion wanted to catch a larger fish so sea lion dove 6 feet lesser than two time the distance that the seal traveled.
To find:
The expression to represent the position of the sea lion in the sea.
Solution:
If the distance traveled by seal is represented by then as per the question statement:
Twice of =
6 lesser than twice of =
- 6
Now, putting the value of = 15
Therefore, the expression to represent the sea lion's position w.r.to sea level.
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Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C.
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
Solution given:
Since the given triangle is isosceles and right angled triangle
perpendicular [p]=base[b]=x
hypotenuse [h]=6
we have
by using Pythagoras law
p²+b²=h²
x²+x²=6²
2x²=36
x²=36/2
x²=18
x=
<u>x</u>=