S = Kt - 16t^2
<span>setting s = 550 </span>
<span>550 = Kt - 16t^2 </span>
<span>this will reach the highest point when v = 0 </span>
<span>t = K/32 </span>
<span>when t = K/32 </span>
<span>550 = K^2/32 - K^2/64 </span>
<span>K^2 = 550*64 </span>
<span>K = 187.62 ft/s</span>
<span>(2/3)(9/5)(5/4)
= (2*9/3*5)</span><span>(5/4)
= (18/15)(5/4)
= 18*5/15*4
= 90/60
= 9/6
= 3/2
</span>
Step-by-step explanation:
(x+2y)(x-2y)
- x^2-2xy+2xy-(2y)^2
- x^2-4y^2
Answer:
[(1/12)(5/5) + (1/20)(3/3)](x hours) = 1
(5/60 + 3/60)x = 1
(8/60)x = 1 we can reduce 8/60 by dividing out a 4
(2/15)x = 1 x both sides by 15/2
x = 15/2
x = 7 1/2 or 7.5 hours
