Answer: To know whether a radical expression is in simplest form or not you should put the numbers and letters inside the radical in terms of prime factors. Then, the radical expression is in the simplest form if all the numbers and letters inside the radical are prime factors with a power less than the index of the radical
Explanation:
Any prime factor raised to a power greater than the index of the root can be simplified and any factor raised to a power less than the index of the root cannot be simplified
For example simplify the following radical in its simplest form:
![\sqrt[5]{3645 a^8b^7c^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3645%20a%5E8b%5E7c%5E3%7D%20)
1) Factor 3645 in its prime factors: 3645 = 3^6 * 5
2) Since the powr of 3 is 6, and 6 can be divided by the index of the root, 5, you can simplify in this way:
- 6 ÷ 5 = 1 with reminder 1, so 3^1 leaves the radical and 3^1 stays in the radical
3) since the factor 5 has power 1 it can not leave the radical
4) the power of a is 8, then:
8 ÷ 5 = 1 with reminder 3 => a^1 leaves the radical and a^3 stays inside the radical.
5) the power of b is 7, then:
7 ÷ 5 = 1 with reminder 2 => b^1 leaves the radical and b^2 stays inside the radical
6) the power of c is 3. Since 3 is less than 5 (the index of the radical) c^3 stays inside the radical.
7) the expression simplified to its simplest form is
![3ab \sqrt[5]{3.5.a^3b^2c^3}](https://tex.z-dn.net/?f=3ab%20%5Csqrt%5B5%5D%7B3.5.a%5E3b%5E2c%5E3%7D%20)
And you know
it cannot be further simplified because all the numbers and letters inside the radical are prime factors with a power less than the index of the radical.
Step-by-step explanation:
For two points (x₁, y₁) and (x₂, y₂), the distance between them is:
d² = (x₁ − x₂)² + (y₁ − y₂)²
The order of points 1 and 2 don't matter. You can switch it:
d² = (x₂ − x₁)² + (y₂ − y₁)²
This is basically the Pythagorean theorem for a coordinate system.
Let's do an example. If you have points (1, 2) and (4, 6), then the distance between them is:
d² = (4 − 1)² + (6 − 2)²
d² = 3² + 4²
d² = 9 + 16
d² = 25
d = 5
If you have points with negative coordinates, remember that subtracting a negative is the same as adding a positive.
For example, the distance between (-1, -2) and (4, 10) is:
d² = (4 − (-1))² + (10 − (-2))²
d² = (4 + 1)² + (10 + 2)²
d² = 5² + 12²
d² = 25 + 144
d² = 169
d = 13
If they're travelling towards each other;
Effective speed = 75+55 = 130
Distance = 338m
Time= distance/ speed
T= 338/130
T= 2.6 hrs
Let's have this equation equal y first. All we have to do is add y to both sides and subtract 4 from both sides.
5x-4=y
Now, to get a parallel line, the y intercept has to change. The y intercept (the -4 in the equation) can be an infinite amount of number but -4.
Let's choose 6. We would have 5x+6=y or you could put it in the way the other equation was, 5x-y=-6.