Always start with the genotypic ratios, because they'll be the same. Since hidden variation is popping out, you can assume that both of the parents are heterozygous. The problems you get will be the F2 ratio of the cross between two homozygous individuals.
1:2:1 is the genotypic ratio for one locus. AA:Aa:aa.
1:2:1 is the phenotypic ratio for incomplete dominance. Incomplete dominance means that the heterozygote expresses differently from either homozygote.
3:1 is the phenotypic ratio for complete dominance.
2:1 is the phenotypic ratio for lethal recessive.
Anxiety and guilt
<span>Ritualistic behavior seen in this disorder is aimed at controlling feelings of anxiety and guilt by maintaining an absolute set pattern of action. Although the person with an obsessive-compulsive disorder may be angry and hostile, the feelings of anger and hostility do not precipitate the rituals. Although the person with an obsessive-compulsive disorder may be embarrassed and ashamed by the ritual or feel hopeless and powerless to the ritual, the basic feelings precipitating the rituals are usually anxiety and guilt.</span>
As it reaches the maximum height speed decreases and subsequently it becomes 0
Answer:

Explanation:
The <em>vapor pressure lowering</em> is a colligative property and it follows Raoult's law.
The <em>vapor pressure lowering</em> of a solvent in a solution, ΔP, is equal to the mole fraction of the solute, Xsolute, multiplied by the vapor pressure of the pure solvent, P°.

ΔP and P⁰ are given:
<u>1. Mole fraction of solute</u>
Thus, you can calculate Xsolute:

<u>2. Moles of solute</u>
Now you can calculate the number of moles of water and the number of moles of solute.
- Number of moles of water = mass in grams / molar mass
- Number of moles of water = 1,250g/18.015 (g/mol) = 69.3866mol
- Xsolvent = 1 - Xsolute = 1 - 0.02513 = 0.97487
- Xsolvent = moles of solvent / moles of solution
- 0.97487 = 69.3866mol / moles of solution
- moles of solution = 71.1752mol
- moles of solute = moles of solution - moles of solvent = 71.1752mol - 69.3866mol = 1.7886mol
<u>3. Mass of urea</u>
Formula:
- Mass = number of moles × molar mass
- Mass = 1.7886 mol × 60.06 g/mol = 107.42 g
You must round to 3 significant figures: 107 g