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vodka [1.7K]
3 years ago
5

Normal cells become cancer cells when

Biology
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

Cancer is unchecked cell growth. Mutations in genes can cause cancer by accelerating cell division rates or inhibiting normal controls on the system, such as cell cycle arrest or programmed cell death. As a mass of cancerous cells grows, it can develop into a tumor.

Explanation:

this is what i found

hope it helps

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A cross between two plants that both have yellow flowers produces 80 offspring plants, of which 38 have yellow flowers, 22 have
zvonat [6]

Always start with the genotypic ratios, because they'll be the same. Since hidden variation is popping out, you can assume that both of the parents are heterozygous. The problems you get will be the F2 ratio of the cross between two homozygous individuals.

1:2:1 is the genotypic ratio for one locus. AA:Aa:aa.

1:2:1 is the phenotypic ratio for incomplete dominance. Incomplete dominance means that the heterozygote expresses differently from either homozygote.

3:1 is the phenotypic ratio for complete dominance.

2:1 is the phenotypic ratio for lethal recessive.

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A female client with obsessive-compulsive disorder has become immobilized by her elaborate handwashing and walking rituals. whic
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Anxiety and guilt

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What do you think happens to the speed of the ball as it reaches its maximum height?
Ahat [919]
As it reaches the maximum height speed decreases and subsequently it becomes 0
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WILL MARK BRAINLIEST 50 POINTS - PLEASE HURRY TAKING A QUIZ
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I belive its A C and E.

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How many grams of urea (non volatile, non electrolyte) must be added to 1250. g water to give a solution with a vapor pressure l
Lady bird [3.3K]

Answer:

\large\boxed{\large\boxed{107g}}

Explanation:

The <em>vapor pressure lowering</em> is a colligative property and it follows  Raoult's law.

The <em>vapor pressure lowering</em> of a solvent in a solution, ΔP, is equal to the mole fraction of the solute, Xsolute, multiplied by the vapor pressure of the pure solvent, P°.

               \Delta P=X_{solute}\times P^0

ΔP and P⁰ are given:

  • ΔP = 1.39mmHg
  • P⁰ = 55.32mmHg

<u>1. Mole fraction of solute</u>

Thus, you can calculate Xsolute:

           1.39mmHg=X_{solute}\times 55.32mmHg\\\\X_{solute}=0.02513

<u>2. Moles of solute</u>

Now you can calculate the number of moles of water and the number of moles of solute.

  • Number of moles of water = mass in grams / molar mass

  • Number of moles of water = 1,250g/18.015 (g/mol) = 69.3866mol

  • Xsolvent = 1 - Xsolute = 1 - 0.02513 = 0.97487

  • Xsolvent = moles of solvent / moles of solution

  • 0.97487 = 69.3866mol / moles of solution

  • moles of solution = 71.1752mol

  • moles of solute = moles of solution - moles of solvent = 71.1752mol - 69.3866mol = 1.7886mol

<u>3. Mass of urea</u>

Formula:

  • Mass = number of moles × molar mass
  • Mass = 1.7886 mol × 60.06 g/mol = 107.42 g

You must round to 3 significant figures: 107 g

8 0
3 years ago
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