Answer:
In humans, blood group is determined by three alleles
,
, and
.
and
are co-dominant whereas
is recessive to other two.
Thus, if a person with blood group O produces offspring with blood group B then the other parent must contain
allele.
The genotype of other person can be
,
, or
.
There is only one condition in which the person can have offspring with blood group O that is, when the other parent is
.
In this condition, the probability of an offspring to have blood group O is 50%.
In other conditions, the probability of an offspring to have blood O is 0%.
The southern hemisphere would be experiencing winter :)
The question is incomplete as it does not have the options which are:
- going to a tailor and having a suit made to fit you
- selecting a lottery prize-winner by means of a random drawing
- going to a shoe store and trying on shoes until you find a pair that fits
- ordering the lunch special at a restaurant without looking at the menu
- picking out a video that you haven't seen yet
Answer:
Going to a shoe store and trying on shoes until you find a pair that fits
Explanation:
Antibodies are the immunoglobulin molecules secreted by the B cells which help the body providing the immunity as they interact with the antigen and help immune system to produce a response.
The variety of the B cells are produced by the body in response to different antigens which produce different type of antibodies. This interaction of antigen and antibodies is known as the complementation and just appear like if you are going to a shop to buys a pair of shoes and tries different shoes to find the best shoe of best size.
Thus, the selected option is correct.
Answer:
Amount remaining = 1.205 * 10²⁴ molecules of urea
Explanation:
The molecular formula of urea is CH₄N₂O. It has a molar mass of 60 g/mol.
Number of moles of urea present in 150 g of urea = mass/molar mass
Number of moles = 150 g/ 60 g/mol = 2.5 moles of urea
I mole of urea contains 6.02 * 10²³ molecules of urea
2.5 moles of urea will contain 2.5 * 6.02 * 10²³ molecules of urea = 1.505 * 10²⁴ molecules of urea
If 3 * 10²³ molecules are removed from 1.505 * 10²⁴ molecules of urea, amount remaining will be:
1.05 * 10²⁴ - 3 * 10²³ = (15.05 - 3) * 10²³ molecules of urea
Amount remaining = 12.05 * 10²³
Amount remaining = 1.205 * 10²⁴ molecules of urea