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musickatia [10]
3 years ago
5

Can you answer the screen shot

Mathematics
2 answers:
Nata [24]3 years ago
5 0

Answer:

Your answer will be 6 and 5/12

Step-by-step explanation:

did it with my calculator

pashok25 [27]3 years ago
4 0

Answer: it's 6 5/12

Step-by-step explanation:

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Help me plaese if u dont mind
777dan777 [17]

Answer:

C)   −2.2y−1.8

Step-by-step explanation:

1.2y+4.5-3.4y-6.3=

Combine Like terms:

=−2.2y−1.8

6 0
3 years ago
MATH. Simplify x+7=2​
HACTEHA [7]

Answer:

x=-5

Step-by-step explanation:

When finding x, we basically have to isolate the variable. By isolating the variable, usually doing the opposite operation helps it.

Addition is the opposite of Subtraction

Multiplication is the opposite of Division

Let's dive into this problem!

x+7=2

(we need to isolate x. basically we need to get rid of this 7. How do we do this? since it is added by seven, we can subtract it by both sides to get rid of it on the x side.)

x+7=2

  -7 -7

x=-5

(subtract 2-(-5), this adds to -5)

This is your final answer.

8 0
4 years ago
Read 2 more answers
12) Add the fractions, and simplify if possible.<br><br> (y+7)/(y^2-y-12) - 2/(y^2-9)
lianna [129]

Answer:

\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}

Step-by-step explanation:

Given the expression

\dfrac{y+7}{y^2-y-12}-\dfrac{2}{y^2-9}

First, factor each denominator:

1. y^2-y-12=y^2-4y+3y-12=y(y-4)+3(y-4)=(y-4)(y+3)

2. y^2-9=(y-3)(y+3)

Now the expression is

\dfrac{y+7}{(y-4)(y+3)}-\dfrac{2}{(y-3)(y+3)}

Now, multiply the first numerator by (y-3) and the second by (y-4) and write the result as a fraction with denominator (y-4)(y+3)(y-3):

\dfrac{(y+7)(y-3)-2(y-4)}{(y-4)(y+3)(y-3)}=\dfrac{y^2-3y+7y-21-2y+8}{(y-4)(y+3)(y-3)}=\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}

This fraction cannot be simplified more.

3 0
4 years ago
Quickkk! -2x-4&gt;-64//what is the value of x
astra-53 [7]

Answer:

x<30

Step-by-step explanation:

u got this

7 0
3 years ago
Read 2 more answers
Plzzzzzzzzzzzzzzz help
mash [69]
Increasing on:
(−∞,1)
Decreasing on:
(1,∞)
5 0
3 years ago
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