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kvv77 [185]
3 years ago
11

Which Two process is it Giving brainliest

Chemistry
1 answer:
Masja [62]3 years ago
8 0

Answer:

C and D!

Explanation:

Don't listen to the other dude above me.

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What is the boiling point of water at an elevation of 1.55×104 ft ?
horsena [70]
The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease 
= 308.14 x 0.05 C = 15.407 deg C 
deduct this amount to 100
100 – 15.407 = 84.593 C 
ANSWER: 85 deg C (rounded to 2 significant figures)
4 0
3 years ago
Convert 13.4 degrees celcius into kelvin​
Alenkasestr [34]

Answer:

286.55K

Explanation:

To convert to kelvin , add 237 .15

13.4\°C + 273.15 = 286.55K

5 0
3 years ago
Read 2 more answers
What is the<br> total charge of 1 proton, 1 electron, and 1 neutron?
iragen [17]

Given parameters:

Number of protons  = 1

Number of electrons = 1

Number of neutrons  = 1

unknown:

Total charge = ?

Atoms are made up of elementary particles of protons neutrons and electrons.

Protons are the positively charged particles in an atom

Electrons are the negatively charged particles

Neutrons do not carry any charges

To find the total charge on an atom; simply find the difference between the number of protons and electrons.

       Total charge  = Number of protons - number of electrons

                               = 1 - 1

       Total charge is 0

Therefore, the total charge is zero, 0

7 0
3 years ago
A solution is made containing 4.6 g of sodium chloride per 250g of water.
lozanna [386]

Answer:

\large \boxed{1.81 \, \%}

Explanation:

\text{Mass percent} = \dfrac{\text{mass of solute} }{\text{mass of solution}} \times 100 \, \%

Data:

Mass of NaCl =      4.6 g

Mass of water = 250    g

Calculations:

Mass of solution = mass of NaCl + mass of water = 4.6 g + 250 g = 254.6 g.

\text{\% m/m} = \dfrac{\text{4.6 g} }{\text{254.6 g}} \times 100 \, \% = \mathbf{1.81 \, \%}\\\\\text{The percent by mass of NaCl is $\large \boxed{\mathbf{1.81 \, \%}}$}

3 0
3 years ago
0.20 L of HNO3 is titrated to equivalence using 0.12 L of 0.2 M NaOH. What is the concentration of the HNO3?
AleksandrR [38]

M_{A}V_{A}=M_{B}V_{B}\\(0.20)(M_{A})=(0.12)(0.2)\\M_{A}=\frac{(0.12)(0.2)}{(0.20)}=\boxed{0.12 \text{ M}}

4 0
2 years ago
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