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3 years ago

HELP ME ILL MARK BRAINLIESTTTT PLSS ASAP

Chemistry

2 answers:

krok68 [10]3 years ago

8 0

Answer:

I think w but I don't know

Alenkasestr [34]3 years ago

7 0

Answer:

Explanation:

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Write any five prevention of cancer

natulia [17]

Answer:

Don't use tobacco or tobacco-containing products

Maintain a healthy diet

Protect yourself from the sun, make sure to use sunscreen

Go to the doctor regularly, for general checkups

Stay physically active

Explanation:

hope this helps :)

8 0

2 years ago

How many moles of water molecules are in 6.81 g of magnesium sulfate heptahydrate (Epsom salts

loris [4]

Answer: 0.34 mol

Justification:

1) Hepta means 7, so heptahyrate means 7 parts of water. On mole of magnesium sulfate heptadydrate has seven moles of water.

2) The formula of magnesium sulfate heptahydrate is:

Mg SO4 . 7 H2O

3) Calcualte the number of moles of the compound by dividing the mass in grams by the molar mass of formula.

molar mass:

Mg: 24.3 g/mol
S: 32.1 g/mol
O4: 4 * 16.0 g/mol = 64.0 g/mol
H2: 2 * 1.0 g/mol = 2.0 g/mol
O: 16 g/mol

Molar mass = 24.3 g/mol + 32.1 g/mol + 64.0 g/mol + 2.0 g/mol + 16.0 g/mol = 138.4 g/mol

number of moles = mass in grams / molar mass = 6.81 g / 138.4 g/mol = 0.049 mol

4) As stated, there are 7 moles of H2O per each mol of heptahydrate compoind, so the number of moles of water is 7 * 0.049 mol = 0.343 mol

Answer: 0.34 mol

8 0

3 years ago

Read 2 more answers

what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?

butalik [34]

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution = M₂= ?

Solution:

M₁V₁ = M₂V₂

0.185 M ×0.025 L = M₂ × 0.0200 L

M₂ = 0.185 M ×0.025 L / 0.0200 L

M₂ = 0.005M.L /0.0200 L

M₂ = 0.25 M

7 0

2 years ago

The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum ra

Makovka662 [10]

The substrate concentration of the enzyme operating at one‑quarter of its maximum rate is = 0.333.

Relationship between Km and substrate concentration is -

Km is the concentration of substrate.It allows the enzyme to achieve half Vmax. High Km enzyme requires a higher concentration of substrate to get Vmax. Since, Km is a constant. If the substrate concentration is increased, it has no effect on it.

An enzyme with a high Km has a low affinity for its substrate. The substrate concentration Km corresponds to the substrate concentration.

The substrate concentration at which the reaction rate of the enzyme-catalyzed reaction is half of the maximum reaction rate Vmax.

The equation is:

V₀ = Vmax [S]

[S] + Km

Here,

V₀ is initial rate,

Km is the dissociation constant between the substrate and the enzyme,

Vmax is the maximum rate, and

S is the concentration of substrate.

taking fraction of V₀ and Vmax :

V₀ = [S]

Vmax [S] + Km

V₀ = 0.5Km = 0.333

Vmax 1.50 + Km

Therefore, the substrate concentration of this enzyme operating at one‑quarter of its maximum rate is = 0.333.

To learn more about substrate concentration,

brainly.com/question/18237939

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3 0

8 months ago

What are the Group 1A and Group 7A elements examples of? my last wuestion

alisha [4.7K]

Representative elements

4 0

2 years ago

Read 2 more answers