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irga5000 [103]
3 years ago
8

What does CH4 stand for

Chemistry
2 answers:
Nadusha1986 [10]3 years ago
5 0

Answer:

CH4 is the element of Methane. It stands for one atom of carbon and four atoms of hydrogen

Explanation:

Sphinxa [80]3 years ago
4 0

Answer:

CH4 stand for methane..

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How many atoms are in sodium hydroxide
Sati [7]

Answer:6 atoms

Explanation:Each NaOH has one Na and one O and one H. Therefore, 2 NaOH has 6 atoms.

3 0
2 years ago
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I neeeddddd heeeellllllppppp I'll give you brainliest
aev [14]

not double replacement

it will be synthesis

they are fusing the two elements

plz mark brainliest


3 0
3 years ago
When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.
uranmaximum [27]
<span>Higher energy = shorter wavelength
Frequency is one cycle over an amount of time (seconds)
So higher frequency = higher energy = shorter wavelength</span>
5 0
3 years ago
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How many moles (of molecules or formula units) are in each sample?
Alexus [3.1K]

The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles

<h3>What is the number of moles?</h3>

The number of moles of a substance is the ratio of the mass of the substance to the molar mass.

In other words; mole = mass/molar mass.

Thus:

  • moles of 18.0 g NO_2 = 18.0/46

                                   = 0.391 moles

  • moles of 1.35 kg CO_2 = 1350/44

                                         = 30.7 moles

  • moles of 46.1 g KNO_3 = 46.1/101.1

                                          = 0.456 moles

  • moles of 191.8 kg Na_2SO_4 = 191800/142

                                                 = 1350 moles

More on the number of moles of substances can be found here: brainly.com/question/1445383

#SPJ1

5 0
2 years ago
Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m
kirza4 [7]
The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
8 0
3 years ago
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