Sa= bw+hw+lw+
(2)
SA=(12*4)+(16*4)+(20*4)+(
)
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364
SA=(12*4)+(16*4)+(20*4)+(
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364
Help me please thanks :)
1 answer:
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Answer:
The width of member is as follows:
b = 3 ft
b = 3 × 12 in.
b= 36 in.
The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in.
Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi
Calculate the net area of the member as follows:
A = (b - ∅) × d
A= (36 - 7/8) × 96
Calculate the maximum axial tensile load by ASD method as follows:
P = f × A
P = 1000 x 3372
P = 3372000 lbs
P = 3372 kips