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3 years ago

The height in feet of a projectile with an initial

Mathematics

1 answer:

enot [183]3 years ago

6 0

Answer:

thus is what i learnd as a baby 64CK NI>GGA DI PSY SH :]

Step-by-step explanation:

You might be interested in

A circle has a circumference of 361\pi361π361, pi. What is the diameter of the circle?

denpristay [2]

Remember, $C=\pi d$ , where $C$ is circumference and tex]d[/tex] is the diameter. They are related by a constant $\pi$ (pi).

We can solve the above equation for d and then substitute our known values.
$C=\pi d$

$d= \dfrac{C}{ \pi } = \dfrac{361 \pi }{ \pi } = 361 \ units$

7 0

3 years ago

Please help and show work if you can

krok68 [10]

Answer:

7. x = 5

8. x = 2, y = 6

9. x = 21, y = 39

Step-by-step explanation:

For a parallelogram, the lengths across intersection are equal.

7. For a parallelogram, the lengths across intersection are equal.

So that,

3x = 4x - 5

4x - 3x = 5

x = 5

8. For a parallelogram, the lengths across intersection are equal.

So that,

2x = 4

x = $\frac{4}{2}$

x = 2

and

y - 1 = 2y -7

7 - 1 = 2y - y

y = 6

x = 2, y = 6

9. For a parallelogram, opposite angles have equal value.

Thus,

3x = (4x - 21)

3x = 4x - 21

x = 21

and

3y = (y + 78)

3y = y + 78

3y - y = 78

2y = 78

y = $\frac{78}{2}$

= 39

y = 39

x = 21, y = 39

4 0

3 years ago

The graph of a function is shown on the coordinate plane below. Identify the rate of change of the function.

earnstyle [38]

Answer:

3.25

Step-by-step explanation:

according to the systematical theorem it would equal 3.25

3 0

2 years ago

Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem

hammer [34]

Answer:

a) $A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) $||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) $A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

Step-by-step explanation:

a) considering the equation:

Minimize $x_{1}^{2} +2x_{2}x^{2} +3x_{3}^{2}+(x_{1} -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}$

$A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$ (matrix A)

vector b

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) If Pxn is matrix B and p-vector d, we have:

minimize $(-6x_{2}+4)^{2} +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}$

$Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]$

$\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]$

$Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1$

$||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) minimize $2(-bx_{2}+4)^{2} +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2} +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2} -\sqrt{3})^{2} +(2x_{1} -16x_{2} -6)^{2}$

in matrix:

$A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

6 0

3 years ago

What is the dimension of height?

MrMuchimi

That’s a Very good question

3 0

3 years ago