Answer:
y = 20°
x = 35°
Explanation:
Equation's:
1) 2y + x + 105° = 180°
2) 3x + x + 2y = 180°
Make y subject in equation 2
3x + x + 2y = 180
4x + 2y = 180
2y = 180 - 4x
y = 90 - 2x
Insert this into equation 1
2(90 - 2x) + x + 105° = 180°
180 - 4x + x + 105 = 180
-3x = -105
x = 35°
Find value of y
y = 90 - 2x
y = 90 - 2(35)
y = 20°
<em>g(x)</em> = <em>x</em>² - <em>x</em> - 6
so
<em>g</em> (-4) = (-4)² - (-4) - 6 = 16 + 4 - 6 = 14
When <em>g(x)</em> = 6, we have
6 = <em>x</em>² - <em>x</em> - 6
<em>x</em>² - <em>x</em> - 12 = 0
Solve for <em>x</em>. We factorize this easily as
(<em>x</em> - 4) (<em>x</em> + 3) = 0
which gives
<em>x</em> - 4 = 0 <u>or</u> <em>x</em> + 3 = 0
<em>x</em> = 4 <u>or</u> <em>x</em> = -3
The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
Read more about transformation at
brainly.com/question/1548871
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92% 23 divided by 25 is 0.92
