4^3 x4^5
A.16^8
B.16x15
C.4^15
D.4^8
2 answers:
the answer is in the picture
A 16^8 is the answer to your question hope this helps
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1. Combining like terms
You would write it like 4/180.
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4.3
Step-by-step explanation:
Answer:
<h3>Question 1</h3>
sec²θ + cosec²θ = 1/cos²θ + 1/sin²θ = (sin²θ + cos²θ)/(sin²θcos²θ) = 1 / (sin²θcos²θ) = [(sin²θ + cos²θ)/sinθcosθ]² = (sinθ/cosθ + cosθ/sinθ)² = (tanθ + cotθ)² <h3>Question 2</h3>
(1 - tan²θ) / (1 + tan²θ) = (1 - sin²θ/cos²θ) / (1 + sin²θ/cos²θ) = (cos²θ - sin²θ) / (cos²θ + sin²θ) = (cosθ + sinθ)(cosθ - sinθ) / 1 = (cosθ + sinθ)(cosθ - sinθ) <h3>Question 3</h3>
sinθ/ (1 - cotθ) + cosθ / (1 - tanθ) = sinθ / (1 - cosθ/sinθ) + cosθ / (1 - sinθ/cosθ) = sinθ/ [(sinθ - cosθ) / sinθ] + cosθ / [(cosθ - sinθ)/cosθ] = sin²θ/ (sinθ - cosθ) + cos²θ/(cosθ - sinθ) = sin²θ/ (sinθ - cosθ) - cos²θ/(sinθ - cosθ) = (sin²θ - cos²θ) / (sinθ - cosθ) = (sinθ + cosθ)(sinθ - cosθ) / (sinθ - cosθ) = sinθ + cosθ
Answer:
wdym bro? what do you mean?
