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3 years ago

Can anyone answer this i need real help..

Mathematics

1 answer:

Maslowich3 years ago

8 0

Step-by-step explanation:

ok multiply the denominator by the whole number to get 8 and add it to the numerator to get 11. the denominator stays the same so you get 11/4

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Anybody know this answer?

AveGali [126]

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5 is the answer

7 0

3 years ago

Read 2 more answers

Help lolz- Acellus Write 0.34 as a fraction using the steps below

Alexxandr [17]

Answer:

Step-by-step explanation:

3.1x10 = 31, and 9x10=90, so the fraction is 31/90, whcih equals 3.44444444 . . .

4 0

3 years ago

– THE ODDS IN FAVOR OF BORIS PENZED WINNING THE HOT

Bezzdna [24]

The probability that Boris will win the contest is:

P = 0.286

<h3>How to get the probability?</h3>

For some given odds a:b, the probability is just computed as the quotient between a and b, which gives:

P = a/b

In this case, the odds are 2:7, so the probability that Boris will win the contest is:

P = 2/7 = 0.286

Written in percentage form, we get:

P = 28.6%

If you want to learn more about probability:

brainly.com/question/24756209

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6 0

1 year ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

Simplify the given expression. (See attachment)

stepladder [879]

Working on x and y first, we get: x6 / x3= x3 and y6/ y12 = 1/ y6 so, we have: 2 x3 / y6
Entering values in original equation, we get:
(2 x3/ y6)^2=4 x^6 / y^12

4 0

3 years ago