5x(x-3) = (x-2)(5x - 1) - 5
5x^2 - 15x = 5x^2 - x - 10x + 2 - 5
5x^2 - 15x = 5x^2 - 11x - 3
5x^2 - 11x - 3 - 5x^2 + 15x = 0
4x - 3 = 0
4x = 3
x = 3/4 or 0.75
Answer:
17 m
Step-by-step explanation:
As shown in the figure, 
is the ground level, 
is the old level of water which was at 20 m below ground level, 
is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.
The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length 
in the figure.
So, 
Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.
Answer:
Yes.
Step-by-step explanation:
It is because 75=9
Hope This Helps.:)
Hello :
f(-4) = 4(-4)+9 = -7
f(-2) = 4(-2)+9 = 1
f(0) = 4(0)+9 = 9
f(2) = 4(2)+9 = 17
the range of the function f(x) = 4x + 9 is : <span>D' = {-7, 1, 9, 17}</span>
Answer:
4
Step-by-step explanation:
Recall that for a function f(x) and for a constant k
f(x+k) represents a horizontal translation for the function f(x) by k units in the negative-x direction.
Hence f(x+k) is simply the graph of f(x) that has been moved left (negative x direction) by k units.
From the graph, we can see that g(x) = f(x+k) is simply the graph of f(x) that has been moved 4 units in the negative x-direction.
hence K is simply 4 units.
