PLEASE HELP !! ILL GIVE BRAINLIEST !!

Mathematics

1 answer:

zimovet [89]2 years ago

7 0

Answer: #1 is the answer. Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.

Step-by-step explanation: Parallel Lines: Definition: We say that two lines (on the same plane) are parallel to each other if they never intersect each other, ragardless of how far they are extended on either side. Pictorially, parallel lines run along each other like the tracks of a train.

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A 208-yard-long road is divided into 16 parts of equal length. Mr. Ward paints a 4-yard-long strip in each part. How long is the

laila [671]

We have been given that a 208-yard-long road is divided into 16 parts of equal length.

Let us find length of each part.

$\text{Length of each part}=\frac{208}{16}$

$\text{Length of each part}=13$

Length of each part will be 13 yards.

We are told that Mr. Ward paints a 4-yard-long strip in each part.

Now we will subtract length of painted strip from length of each equal part to find length of unpainted strip of each part of the road.

$\text{Length of unpainted strip}=13-4$

$\text{Length of unpainted strip}=9$

Therefore, length of each unpainted strip will be 9 yards.

5 0

2 years ago

During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?

Novosadov [1.4K]

So basically ...

You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

280 × 100 = 28,000

And then we divide,

28,000 ÷ 14 = 2000

The post office sold 2000 stamps!

Hope this helped! :)

6 0

2 years ago

In the diagram below, GH is parallel to DE . If GH is 3 more than EH FH=10, and DE=12 find the length of EH. Figures are not nec

steposvetlana [31]

Answer: 5

Step-by-step explanation:

Since $\overline{GH} \parallel \overline{DE}$ , by the corresponding angles theorem, $\angle FGH \cong \angle FDE, \angle FHG \cong \angle FED$ . This means $\triangle FGH \sim \triangle FDE$ by AA.

As corresponding sides of similar triangles are proportional,

$\frac{10}{x+3}=\frac{10+x}{12}\\(10)(12)=(10+x)(x+3)\\120=x^{2}+13x+30\\x^{2}+13x-90=0\\(x+18)(x-5)=0\\x=-18, 5$
However, as distance must be positive, we consider the positive solution, x=5.