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Oksi-84 [34.3K]
3 years ago
11

What times what equals 65

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0
5 x 13 = 65. 65 x 1
13 x 5
130 x 1/2
260 x 1/4
6.5 x 10


These are just a few examples
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The correct answer is Line ST I think I’m not sure
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A landscaper is designing a flower garden in the shape of a trapezoid. She wants the shorter base to be 3 yards greater than the
wariber [46]

The formula for the area of a trapezium is as follows:

<span>area=<span>12</span>(a+b)h

</span> Let a be the shorter base. Then a = h + 3.
Let b be the longer base. Then b = h + 7.

Substituting these values for a and b in the general formula gives: <span>
area = 225 = <span>12</span>(h+3+h+7)h = <span>h^2</span>+5h</span>

So you need to solve the following quadratic:

<span><span>h^2</span>+5h−225=0</span>


Step 1: Use quadratic formula with a=1, b=5, c=-225.

<span>h=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>h=<span><span><span>−<span>(5)</span></span>±<span>√<span><span><span>(5)</span>2</span>−<span><span>4<span>(1)</span></span><span>(<span>−225</span>)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>h=<span><span><span>−5</span>±<span>√925</span></span>2</span></span><span><span>h=<span><span><span>−5/</span>2</span>+<span><span><span><span>5/2</span><span>√37</span></span><span> or </span></span>h</span></span></span>=<span><span><span>−5/</span>2</span>+<span><span><span>−5/</span>2</span><span>√37

</span></span></span></span>Answer:<span><span>h=<span><span><span>−5/</span>2</span>+<span><span><span><span>52</span><span>√37</span></span><span> or </span></span>h</span></span></span>=<span><span><span>−5/</span>2</span>+<span><span><span>−5/</span>2</span><span>√<span>37</span></span></span></span></span>
4 0
3 years ago
Please help!
Mrrafil [7]

Answer:

\sf C. \quad \dfrac{1}{9}

Step-by-step explanation:

<u>Addition Law for Probability</u>

\sf P(A \cup B)=P(A)+P(B)-P(A \cap B)

Given:

  \sf P(A)=\dfrac{1}{3}=\dfrac{3}{9}

  \sf P(B)=\dfrac{2}{9}

  \sf P(A \cup B)=\dfrac{4}{9}

Substitute the given values into the formula and solve for P(A ∩ B):

\implies \sf P(A \cup B) = P(A)+P(B)-P(A \cap B)

\implies \sf \dfrac{4}{9} = \sf \dfrac{3}{9}+\dfrac{2}{9}-P(A \cap B)

\implies \sf P(A \cap B) = \sf \dfrac{3}{9}+\dfrac{2}{9}-\dfrac{4}{9}

\implies \sf P(A \cap B) = \sf \dfrac{3+2-4}{9}

\implies \sf P(A \cap B) = \sf \dfrac{1}{9}

4 0
1 year ago
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For A and B, use the indicated operations to find the answer
anastassius [24]

Step-by-step explanation:

Your question is not well understood

4 0
2 years ago
If the kite is 500 feet of string how high is it above the ground if the horizontal distance between Tyler and the kite is 300 f
laiz [17]

Pythagorean Theorem:  

500^2 = 300^2 + x^2  

250,000 = 90,000 + x^2  

160,000 = x^2  

x = +/- 400 use the positive root  

height is 400ft

6 0
3 years ago
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