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bekas [8.4K]
4 years ago
6

What is the simplified expression for 3^3• 3^3/3^4?A. 3^0B.3^1C.3^2D.3^4​

Mathematics
2 answers:
Klio2033 [76]4 years ago
8 0

Answer:

C

Step-by-step explanation:

It is C because multiplying exponents means you add the top number while dividing means subtract.

Andreyy894 years ago
4 0

Answer:

Its C

Step-by-step explanation:

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Abby bought one package of cookies that weighed 24 ounces and another package that weighed 2 pounds 2 ounces. What was the combi
BARSIC [14]

Answer: If you place 10 packages per box, each box will weigh 10(3 lb 4 oz). This is 30 lb 40 oz. For 4 boxes you would have 4(30 lb 40 oz). This is 120 lb 160 oz. To put you answer in the correct form you need to change the 160 oz to pounds and ounces. 16 oz is equal to 1 pound, so divide 160 by 16. The 160 oz is equivalent to 10 lbs. Therefore the total weight of 4 boxes is 120 + 10 which equals 130 lbs.

6 0
3 years ago
The volume of a cone is 1004.8 in.³. The height of a cone is 15 inches. What is the radius of the con rounded to the nearest inc
sergiy2304 [10]
\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad 
\begin{cases}
r=radius\\
h=height\\
-----\\
h=15\\
V=1004.8
\end{cases}\implies 1004.8=\cfrac{\pi r^2 15}{3}
\\\\\\
3\cdot 1004.8=15\pi r^2\implies \cfrac{3\cdot 1004.8}{15\pi }=r^2\implies \sqrt{\cfrac{3\cdot 1004.8}{15\pi }}=r
8 0
4 years ago
A​ 150-pound person uses 5.1 calories per minute when walking at a speed of 4 mph. How long must a person walk at this speed to
wolverine [178]

Let 't' represent the time of the walk in minutes.

5.1*t = 220

t = 43.14 min

The person needs to walk at least 43.14 minutes to but at least 220 calories.

6 0
3 years ago
Is this correct? Graph image using transformation given.
Basile [38]
Yes because you did the exact same thing on the different side
6 0
3 years ago
I need help.................................
pantera1 [17]

Answer:

Option (C)

Step-by-step explanation:

AB and BC are perpendicular to each other at point B.

Ordered pairs representing points A and B are (-3, -1) and (4, 4)

Slope of AB, (m_1) = \frac{y_2-y_1}{x_2-x_1}

                             =\frac{(4+1)}{4+3}

                             =\frac{5}{7}

Let the slope of perpendicular line BC = m_2

By the property of perpendicular lines,

m_1\times m_2=-1

\frac{5}{7}\times m_2=-1

m_2=-\frac{7}{5}

Equation of line BC → y - y' = m₂(x - x')

y-4=(-\frac{7}{5})(x-4)

y = -\frac{7}{5}x+\frac{28}{5}+4

5y = -7x + 28 + 20

7x + 5y = 48

-7x - 5y = -48

Option (C) will be the answer.

5 0
3 years ago
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