Answer:
-42x^4 + 6x^3 + 24x^2
Step-by-step explanation:
1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207
One inch is the greater measure
<h2><u>Complete Question: </u></h2>
Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.
1. 
2. 
3. 
4. 
5. 
<h2><em><u>The answers:</u></em></h2>
1.
- Similar (S)
2.
- Similar (S)
3.
- Dissimilar (D)
4.
- Dissimilar (D)
5.
- Dissimilar (D)
Note:
- Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
- Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.
Thus:
1.
- They have equal denominator. <u><em>Both fractions are similar (S).</em></u>
2.
- They have equal denominator. <em><u>Both fractions are similar (S).</u></em>
3.
- They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>
4.
- They have equal denominator. <u><em>Both fractions are dissimilar (D).</em></u>
5.
- They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>
Therefore, the fractions in <em><u>1 and 2 are similar (S)</u></em> while those in <em><u>3, 4, and 5 are dissimilar (D).</u></em>
<em><u></u></em>
Learn more here:
brainly.com/question/22099172
Answer:
Radius = r = 7.5
Diameter = d = 15
Circumference = C = 15π
Step-by-step explanation:
We are given the image of a circle with a straight line passing through the center of the circle and touching its edges. Such a line is known as the diameter of the circle. From the image we can see the length of the diameter of the circle is d = 15 units.
Radius is define as half of the diameter. Since the diameter is 15 units, the radius of the given circle will be half of 15 which is r = 7.5 units.
Circumference of the circle = C = 2πr
Using the value of radius(r), we can write the circumference as:
C = 2π(7.5) = 15π