Answer:
B.
Step-by-step explanation:
Using the future value formula, it is found that you would need to deposit $272.95 in the account each month.
<h3>What is the future value formula?</h3>
It is given by:
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
In which:
- n is the number of payments.
For this problem, considering that there are monthly compoundings, the parameters are:
r = 0.08/12 = 0.0067, V(n) = 300000, n = 25 x 12 = 300.
Hence we solve for P to find the monthly payment.
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
![300000 = P\left[\frac{(1.0067)^{299}}{0.0067}\right]](https://tex.z-dn.net/?f=300000%20%3D%20P%5Cleft%5B%5Cfrac%7B%281.0067%29%5E%7B299%7D%7D%7B0.0067%7D%5Cright%5D)
1099.12P = 300000
P = 300000/1099.12
P = $272.95.
You would need to deposit $272.95 in the account each month.
More can be learned about the future value formula at brainly.com/question/24703884
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(((1/y - 1) + (5/12)) = (-2/3y - 3))
((((1)(12)/12(y - 1) + (5(y + 1)/12(y + 1) = (-2/3y - 3))
((12/12y - 12) + (5y + 5/12y - 12)) = (-2/3y - 3))
((5y + 17/12y - 12) = (-2/3y - 3)
(12y - 12/5 + 17) × (5y + 17/12y - 12) = (-2/3y - 3)(12y - 2/5 + 17)
y = -21y + 4/66y - 66
y = -7/22 - 2/33
y = -25/66
Answer:
20 miles per hour
Step-by-step explanation:
Given that the train left for London, and after 9 hours later, a car traveling 80 miles per hour tried catching up to the train. After 3 hours, the car caught up
Which means that the car travelled the same distance in 3 hours as the train travelled in 9 + 3 = 12 hours
Let the distance be d
Given the speed of car is 80 miles per hour
We know that 

d = 240 miles
Now for the train Average speed = total distance / total time taken
Average speed of the train =
= 20 miles per hour
Step-by-step explanation:
since maxima is a point in which a function within a range gives maximum value. And its value is called maximum value of the function over an interval.