What is the range of 2,3,2
1 answer:
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Answer:
f'(x) > 0 on and f'(x)<0 on
Step-by-step explanation:
1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:
To find its decreasing interval :
2) Then let's find the critical point of this function:
2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x''≈0.37 for e≈2.72
3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.
