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2 years ago

30 POINTS!!! ANSWER ASAP!!

Mathematics

2 answers:

Yuki888 [10]2 years ago

8 0

Answer:

the last answer or d....

Step-by-step explanation:

Firlakuza [10]2 years ago

6 0

Answer:

Step-by-step explanation:

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Round .593 to the nearest tenths place value.

Over [174]

Answer:

Step-by-step explanation:

The tenths place is on the other side of the decimal so you have to star from 3. if the 3 was the number 5 or higher you would round the 9 up to ten, but since it is lower you leave the 9 alone and then move on to the next number which is 5. The 5 would be rounded up to 6 because the 9 next to it is higher than 5. So far you have 0.6. looking at the 0 we would round up to 1 because the 6 is higher than 5. the result is 1.0 or 1.

5 0

3 years ago

N which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?

OLEGan [10]

Answer:

53,901

Step-by-step explanation:

Here is the complete question :

In which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?

43,567

45,248

53,901

562,011

In the number 245,093 :

3 = units

9 = tens

0 = hundred

5 = thousand

4 = ten thousand

2 = hundred thousand

the value of 5 in the number is 5000. the number that would have a value that it 10 times greater than 5 in 245,093 must occupy the value of ten thousand.

looking through the options, it is only in 53,901 that 5 occupies a value of ten thousand

6 0

3 years ago

Look at the picture

IRISSAK [1]

Answer:

x = 10

Step-by-step explanation:

In the last step, you can see that the fraction $\frac{1}{5}$ has been multiplied by its reciprocal $\frac{5}{1}$ , making it cancel out. The reciprocal has been multiplied to both sides, so all you need to do is multiply $\frac{6}{3}$ · $\frac{5}{1}$ :

6 · 5 = 30

3 · 1 = 3

<u><em>So now you should have the fraction:</em></u>

x = $\frac{30}{3}$

<u><em>But, you can still simplify the fraction by dividing 30 by 3:</em></u>

x = 10

7 0

3 years ago

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The

zavuch27 [327]

The standard deviation of the frequency distribution is 5.54

<h3>How to determine standard deviation?</h3>

The table of values is given as:

x f(x)

0-3 13

4-7 13

8-11 10

12-15 11

16-19 0

20-23 3

Rewrite the table by calculating the class midpoints:

x f(x)

1.5 13

5.5 13

9.5 10

13.5 11

17.5 0

21.5 3

Start by calculating the mean using:

$\bar x = \frac{\sum fx}{\sum f}$

This gives

$\bar x = \frac{1.5 * 13 + 5.5 * 13 + 9.5 * 10 + 13.5 * 11 + 17.5 * 0 + 21.5 * 3}{13 + 13 + 10 + 11 + 0 +3}$

Evaluate

$\bar x = 7.98$

The standard deviation is then calculated as:

$\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f }}$

So, we have:

$\sigma= \sqrt{\frac{13 * (1.5 - 7.98)^2 + 13 * (5.5 - 7.98)^2 + (9.5 - 7.98)^2 * 10 + (13.5 - 7.98)^2 * 11 + (17.5 - 7.98)^2 * 0 + (21.5 - 7.98)^2 * 3}{13 + 13 + 10 + 11 + 0 +3}}$