What are you asking to solve?
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1
Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;
so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
;
The actual width of the room is 20 ft and the actual length of the room is 15 ft
Since on the scale, 2 in : 5 ft and the width of the room on the drawing is 8 in.
Let the actual width of the room is w.
The ratio of the drawing to actual width is 8 in : w
So, 2 in : 5 ft = 8 in : w
2 in/5 ft = 8 in/w
So, w = 8 in × 5 ft/2 in
w = 4 × 5 ft
w = 20 ft
Also, the length of the room on the drawing on the drawing is 6 in.
Let the actual length of the room is L.
The ratio of the drawing to actual length is 6 in : L
So, 2 in : 5 ft = 6 in : L
2 in/5 ft = 6 in/L
So, L = 6 in × 5 ft/2 in
L = 3 × 5 ft
L = 15 ft
So, the actual width of the room is 20 ft and the actual length of the room is 15 ft.
Learn more about scale drawing here:
brainly.com/question/25324744
19-(-39)
19+39=58
is solution as
the two end points are 19 and -39 we should subtract then we get the distance between
