A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
256. Since each side is congruent, the length equals 8. 8 times 8 equals 64. Divide it by 2 to find the area of the triangle. 64 divided by 2 equals 32. Since there are 8 congruent triangles, 32 x 8 equals 256.
<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
The answer would be A. 15mi
Answer:
14/29. reduced form............
