Answer:
404 cm³ Anyway... Look down here for my explanation.
Step-by-step explanation:
Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.
We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area 88.8/360*area of circle - ½*7*788.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
Volume of water = cross-sectional area * length
13.5 * 30 cm³
404 cm³
Answer:
x = 15.4
Step-by-step explanation:
Because this is a right triangle, you can use the pythagorean theorem to find the length of the hypotenuse. the theorem is a^2 + b^2 = c^2
so
9^2 + 12.5^2 = c^2
solving this will give you 15.4
The question is incomplete. Here is the complete question:
A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?
Answer:
2.5 square feet per hour
Step-by-step explanation:
Given:
Area covered by a machine = 
Time taken to cover the given area = 
Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.
Here, the first quantity is the area covered and the second quantity is the time taken.
So, unit rate is the area covered by the machine in 1 hour.
In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,
Thus, the unit rate is 2.5 square feet per hour.
