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3 years ago

Please I need this question fast

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

We have a linear function $\displaystyle\bf y=\underbrace{k}_{gradient}x+b$ and we know that $\displaystyle\bf \left \{ {{-2\cdot-3+b=2} \atop {-4\cdot -2+b=k}} \right. => \left \{ {{b=-4} \atop {b+8=k} \right. => k=8-4=4 \\\\Answer: \boxed{B) \quad k=4}$

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Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Simplify to create an equivalent expression. −y−3(−3y+5)

navik [9.2K]

Answer:

$\large\boxed{-y-3(-3y+5)=8y-15}$

Step-by-step explanation:

$-y-3(-3y+5)\qquad\text{use the distributive porerty}\ a(b+c)=ab+ac\\\\=-y+(-3)(-3y)+(-3)(5)\\\\=-y+9y-15\qquad\text{combine like terms}\\\\=(-y+9y)-15\\\\=8y-15$

4 0

4 years ago

According to the synthetic division below, which of the following statements are true?

kykrilka [37]

Answer:

Options (A) and (D)

Step-by-step explanation:

We can write the given division as,

$\frac{2x^2+6x-8}{x+5}=2x-4+\frac{12}{x+5}$

Option (A)

When (2x² + 6x - 8) is divided (x + 5), the remainder is 12.

True.

Option (B)

When (2x² + 6x - 8) is divided (x - 5), the remainder is 12.

False.

Option (C)

When x = 5,

2x² + 6x - 8 = 12

2(5)² + 6(5) - 8 = 50 + 30 - 8

= 72

False.

Option (D)

When x = -5,

2(-5)² + 6(-5) - 8 = 50 - 30 - 8

= 12

True.

Option (E)

(x - 5) is a factor of 2x² + 6x - 8

If (x - 5) is a factor value of 2x² + 6x - 8 should be zero.

False.

Option (F)

(x + 5) is a factor of 2x² + 6x - 8

If (x + 5) is a factor then by substituting x = -5 in the expression value should be zero.

But the value is 12.

False.

5 0

3 years ago

Look at the following expression.

FinnZ [79.3K]

C is not equivalent to all the expressions

3 0

3 years ago

Pls answer its my test quick and points

baherus [9]

Answer:

so sorry i really really dont know

8 0

3 years ago

Read 2 more answers

Please I need this question fast​

Please I need this question fast