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3 years ago

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Caleb was recently hired for a job with an annual income of $35,000. Using the federal income rate of 15 %, what amount should C

aleb expect to
pay in federal income tax?

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

<h2 /><h2><em><u>an</u></em><em><u>swer</u></em><em><u> will</u></em><em><u> be</u></em><em> </em><em>5</em><em>2</em><em>5</em><em>0</em></h2>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em> $35000 \times \frac{15}{100} = 350 \times 15 = 5250$ </em>

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The given histogram represents <span>the number of hamburgers students ate in a month :
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A one-parameter family of solutions of the de p' = p(1 − p) is given below.

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Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

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Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

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A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

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Answer:

The original duration of the tour is 18 days.

Step-by-step explanation:

Let

the number of days spent be T

Daily expenses be D

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total tour expenses was 360

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$D = \frac{360}{T}$ -------------(1)

If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3

$(D + 4) \cdot(T -3) = 360$ ---------------(2)

Expanding the eqaution(2)

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Substituting the value of D

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T -12 = 360$

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 360 + 12$

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 372$

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$( \frac{1080}{T}) + 4T= 372 - 360$

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Solving the quadratic equation we get

T = 18 and T = -15

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Substituting in equation (1) we get

$D = \frac{360}{18}$

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kicyunya [14]

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